My solution to a “Daily Coding Problem” that I received in my mail today.
Given a 2-D matrix representing an image, a location of a pixel in the screen and a color
C, replace the color of the given pixel and all adjacent same colored pixels with C.
For example, given the following matrix, and location pixel of (2, 2), and ‘G’ for green:
B B W
W W W
W W W
B B B
Becomes
B B G
G G G
G G G
B B B
Here’s my solution in Typescript. I actually like this problem a lot 🙂
oneFiftyOne(matrix: string[][], i:number, j: number, target: string): string[][] {
if(matrix == null) {
return [];
}
if(i < 0 || i >= matrix.length || j <0 || j>= matrix[i].length) {
return matrix;
}
if(matrix[i][j] == target) {
matrix[i][j] = "C";
} else {
return matrix;
}
this.oneFiftyOne(matrix, i+1, j, target);
this.oneFiftyOne(matrix, i-1, j, target);
this.oneFiftyOne(matrix, i, j+1, target);
this.oneFiftyOne(matrix, i, j-1, target);
return matrix;
}
As usual, if you find any of my posts useful support me by buying or even trying one of my apps on the App Store.
Also, if you can leave a review on the App Store or Google Play Store, that would help too.
Comments